which term of AP 3,15,27,39 will be 132 more than its 54th term
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a1=3
d=12
an=a54+132
a+(n-1)d=a+53d+132
3+(n-1)12=3+53×12+132
3+(n-1)12=3+636+132
3+(n-1)12=771
3+12n-12=771
12n-9=771
12n=780
n=780/12
n=65
65th term will be more than its 54th term.
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