Which term of AP : 3, 15, 27, 39.... will be 132 more than its 54th term
Answers
Answered by
22
required term = t54 + 132
here, a=3 d = 12
so t54 = a+53d
= 3+636= 639
so required term is 639+132
= 771
here, a=3 d = 12
so t54 = a+53d
= 3+636= 639
so required term is 639+132
= 771
Answered by
23
Hey
Here is your answer,
a = 3
d = 15-3
= 12
By using the formula , An = a + (n-1) d
An = A54 + 132
a + (n-1) d = a + (n-1)d +132
3 + (n-1) 12 = 3 + 53 x 12 +132
12n - 12 = 636 + 132
12n = 780
n = 780/12
n = 65
Therefore 65 is the term.
Hope it helps you!
Here is your answer,
a = 3
d = 15-3
= 12
By using the formula , An = a + (n-1) d
An = A54 + 132
a + (n-1) d = a + (n-1)d +132
3 + (n-1) 12 = 3 + 53 x 12 +132
12n - 12 = 636 + 132
12n = 780
n = 780/12
n = 65
Therefore 65 is the term.
Hope it helps you!
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