which term of AP:3,15,,27,39,......will be132 more than it's 54th term??
please explain by step by step
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Answer:
Given-: a= 3, d= 12
To find-: nth term
Sol-: Tn = T54 +132
a+(n-1)d = a+(n-1)d+132
3+(n-1)12= 3+(54-1)12+132
3+(n-1)12=3+(53*12)+132
3+(n-1)12=135+636
(n-1)12=771-3
(n-1)=768/12
n=65
Hence, 65 term of the ap will be 132 more than 54th term
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