which term of AP 3,8,13,18........will be 130 more than its 31st term??
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A = 3
n = 54
d = 12
we know that
a + ( n - 1 ) d
= 3 + ( 54 - 1 ) 12
= 3 + 53 × 12
= 3 + 636
= 639
Now
132 + 639 = 771
771 = 3 + (n - 1) 12
768/12 + 1 = n
64 + 1 = n
n = 65
Therfore 65th term term 132 more than 54th
n = 54
d = 12
we know that
a + ( n - 1 ) d
= 3 + ( 54 - 1 ) 12
= 3 + 53 × 12
= 3 + 636
= 639
Now
132 + 639 = 771
771 = 3 + (n - 1) 12
768/12 + 1 = n
64 + 1 = n
n = 65
Therfore 65th term term 132 more than 54th
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