Question

which term of AP 36,31,26,21 is the first negative term?
asap

Answer 1

$an < 0$
36+(n-1)d is less than 0
d=31-36=-5
36+(n-1)-5 is less than 0
(n-1)-5 is greater than -36
(n-1)is greater than -36/-5
(n-1)is greater than 7.2
n is greater than 7.2+1
n is greater than 8.2
n=9
Hence,9th term of the ap is it's first negative term

Answer 2

The first negative term is 9th term

Step-by-step explanation:

AP 36,31,26,21

First term = a = 36

Common difference = d = 31-36=26-31 = -5

Formula of nth term =$a_n=a+(n-1)d$

We are supposed to find  first negative term

So, $a+(n-1)d<0$

$36+(n-1)(-5)<0$

$(n-1)(-5)<-36$

$(n-1)(-5)<-36$

$(n-1)<7.2$

$n<8.2$

So, The first negative term must be 9th term

Hence The first negative term is 9th term

#Learn more :

Which term of an A.P 121,117,113........is the first negative term and first second negative term

https://brainly.in/question/1592575