Math, asked by durvesh97, 10 months ago

which term of AP 50,40 ,30,20 is the number - 940​

Answers

Answered by shrikantpo70
21

Answer: n = 100 terms

Step-by-step explanation:

Here a = 50 first term

Difference d = 40-50 = -10

An = -940

To find no of terms

An = a+(n-1)d

-940 = 50+ -10n+10

Please mark as brainliest

-10n= -940-60

-10n= -1000

n = -1000/-10

n =100


durvesh97: plz give answer of 1 more questions
basudebnayak1604: OK
durvesh97: find S10 for an ap 1 upon 6 ,1 upon 4 ,1 upon 3
durvesh97: the 41st term of AP exceed the 19th term by 154 . find the common difference of an ap
Answered by basudebnayak1604
33

Answer:

a=50

d=40-50 = -10

an =-940

an=a+(n-1)d

-940= 50+(n-1)(-10)

-940-50=(n-1)(-10)

-990=(n-1)(-10)

-990/-10=n-1

99+1=n

100=n

100th term of this ap is -940


durvesh97: plz give 1 more question answer
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