Which term of Ap 8,14,20.....will be 7 more than its 41th term
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AP :8,14,20,26...
a=8
d=14−8=6
Let T
n
=T
41
+72
a+(n−1)d=a+40d+72
⇒a+(n−1)d−a−40d=72
⇒d(n−1−40)=72
⇒6(n−41)=72
x−41=12
x=12+41
x=53
Required term = 53
53
th
term of AP will be 72 more than its 41
th term
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