Which term of ap 9,12,15,18... will be 39 more than its 36th term?
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we apply formula a+38d , a+35d so we find the term
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a= 9 a,=12
d = 12 -9 =3
an= a +(n-1 )d
= a+35d +39
= 9+35×3+39
9 +105 +39
153
d = 12 -9 =3
an= a +(n-1 )d
= a+35d +39
= 9+35×3+39
9 +105 +39
153
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