which term of Ap 92,88,84,80...is0?
Answers
Answered by
1
Let nth term be zero.
We know, a(n) = a + (n-1)d
Where, a(n) = nth term
a=first term
n= number of term
d=common difference
Here, we can see that common difference, d=88-92 = -4
=> 0 = 92 + (n-1)(-4)
=> n-1 = 92÷4
=> n-1 = 23
=> n = 24
Hence 24 is the answer
We know, a(n) = a + (n-1)d
Where, a(n) = nth term
a=first term
n= number of term
d=common difference
Here, we can see that common difference, d=88-92 = -4
=> 0 = 92 + (n-1)(-4)
=> n-1 = 92÷4
=> n-1 = 23
=> n = 24
Hence 24 is the answer
Answered by
0
Hi friend,
Here is your answer,
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____________________________________________________________
First term (a) = 92
Common difference (d) = 88 - 92
= -4
Number of terms = n
Tn = 0
Tn = a + (n - 1)d
0 = 92 + (n - 1)(-4)
-92 = (-4)(n - 1)
23 = n - 1
n = 24
24th term of this A.P. is 0.
__________________________________________________________
HOPE THIS HELPS YOU !!
PLS MARK AS BRAINLIEST !!
☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺
Here is your answer,
☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺
____________________________________________________________
First term (a) = 92
Common difference (d) = 88 - 92
= -4
Number of terms = n
Tn = 0
Tn = a + (n - 1)d
0 = 92 + (n - 1)(-4)
-92 = (-4)(n - 1)
23 = n - 1
n = 24
24th term of this A.P. is 0.
__________________________________________________________
HOPE THIS HELPS YOU !!
PLS MARK AS BRAINLIEST !!
☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺
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