Question

Which term of AP is 1,7,13,19 is 55

Answer 1

Answer:

10th Term

Step-by-step explanation:

Since , a=1 (first term of A.p)

           d=6(difference b/w 2 consecutive terms)

           an=55(last term of A.P)

           n=(nth term of A.P)

And we know,

                                        >>>an=a+d(n-1)

                                        >>>55=1+6(n-1)

                                        >>>54/6=n-1

                                        >>>9+1=n

                                        >>>10=n

Thus, 55 is the 10th term of this A.P

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Answer 2

Answer:

10 th Term

Step-by-step explanation:

A.P= 1,7,13,19

a=1

t1= 1, t2= 7, t3= 13 t4=19

d= t2-t1 = 7-1= 6

= t3-t2=13-7= 6

= t4-t3= 19-13=6

d=6, a=1, n=?, tn=55

[tn= (n-1)d]

55= 1+(n-1)-6

6(n-1)= 55-1

6(n-1)=54

n-1=54÷6

n-1= 9

n= 9+1

n= 10

Therefore , 55 is 10th term of A.P.