Question

Which term of AP is 147 is 25

Answer 1

Answer:

$1,4,7,........25$

$a = 1 \\ d = 4 - 1 = 3$

$an = a + (n - 1)d \\ = 1 + (n - 1)3 \\ = 1 + 3n - 3 \\ an = 3n - 2$

$now \: equate \: {n}^{th} term \: of \: ap \\ an \: = 3n - 2 = 25 \\ 3n - 2 = 25 \\ 3n = 25 + 2 \\ 3n = 27 \\ n = \frac{27}{3} \\ n = 9$

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