Question

which term of AP is 3, 16 ,29 42 is 627 ​

Answer 1

Answer:

your answer is in the attached picture

Step-by-step explanation:

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Answer 2

49th

Step-by-step explanation:

Given -

• A.P = 3 , 16 , 29 , 42...
• First term (a) = 3
• Common difference (d) = a2 - a1

= 16 - 3

= 13

To find -

• Which term of the A.P is 627.

Solution -

Let 'nth' term of the A.P be 627.

The formula for the 'nth' term of the A.P is

$\Large \bf \underline\orange{a(n) = a + (n − 1) × d}$

Where ,

a = First term

d = Common difference

n = number of terms

a(n) = nth term

After putting the values in the formula , we get ,

$⟹ \large 627 = 3 + (n - 1)13$

$⟹\large 627 - 3= (n - 1)13$

$⟹\large 624= (n - 1)13$

$⟹ \large \cancel\frac{624}{13} = \normalsize(n - 1)$

$⟹ \large 48 = n - 1$

$⟹ \large 48 + 1 = n$

$⟹ \large\green{ \boxed{49}}$

Therefore , 49th term of the A.P is 627.