Question

Which term of AP is 4, 11 18 25 is 42 more than its 25th term

Answer 1

d = 11 - 4 = 7
....................
a(1) = 4
.....................
a(n) = 4 +(n-1)(7)
...............................
a(?) = 42 + a(25)
a(?) = 42 + 4 + 24×7 = 42 + 4 + 168 = 214
...................................................................
4 + (n-1)(7) = 214 →n-1 = 210/7 = 30 →n = 31

Answer 2

Answer:

31st term is 42 more than its 25th term.

Step-by-step explanation:

We are given with AP: 4, 11 18 25, .............

From here

$a=4$

$d=11-7$

Hence, we can say that each term is 7 greater than the previous term.

Now, if we need to determine the term which is 42 more than its 25th term, 42 more means 6(7) i.e. sic terms ahead of 25th term.

It means 25+6=31

31st term is 42 more than its 25th term.

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