which term of AP is first negative term 123, 121, 119
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Given:first term(a)= 121
common difference (d)= 117- 121 = -4
∵ n th term of an AP
an = a + (n – 1)d
⇒121+(n-1) ×(-4)
⇒121-4n+4
⇒12+4-4n
⇒125 -4n
an= 125 -4n
For first negative term , an <0
⇒ 125-4n<0
⇒125<4n
⇒4n>125
⇒n>125/4
⇒n> 31 1/4
least integral value of n= 32
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Answer:
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Step-by-step explanation:
119 is the first negative term
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