Question

Which term of arithmetic progression 5,15,25 ...
will be 130 more than its 31st term?

Answer 1

Answer:

Answer is 44

Step-by-step explanation:

a=5

d=15-5=10

an=a+(n-1)d

an=5+(31-1)10

=5+300

So the 31 term will be 305

130 more than the 31 term is =130+305=435

Now:

an=a+(n-1)d

435=5+(n-1)10

430/10=n-1

43=n-1

N=44