Which term of arithmetic progression 5,15,25,......will be 130 more than it's 31 st term
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Step-by-step explanation:
Ap:5,15,25......
a=5 ..(1)
d=10 ..(2)
we know that 31st term can be written as a+30d
As per data the ‘n’th number will be 130+a+30d
Applying 1,2
130+5+30(10)=435 .....an
an = a+(n-1)d
435=5+(n-1)10
435-5=(n-1)10
430/10=(n-1)
43=n-1
43+1=n
n=44
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