Question

which term of arthemic sequence 1,6,11,.......is 56?
a)11
b)12
c)13
d)14
please answer fast
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Answer 1

Step-by-step explanation:

a`n = a + (n-1)d

=> 56 = 1 + (n-1) × 5

=> 55/5 = n-1

=> n = 11 +1

=> n= 12

So, option (b) is the correct answer.

Answer 2

Answer:

b

Step-by-step explanation:

here first term i.e a= 1

common difference i.e d= 5

Tn = a+(n-1)d

56 = 1 + (n-1) 5

55 = (n-1) 5

11 = (n-1)

n = 12