Question

Which term of arthmatic progress 4,9,14,19,.....is 109

Answer 1

Hey!!

Given AP

4, 9, 14, 19,..... 109


Here, first term a = 4

Common Difference d = ( a2 - a1 ) = 9 - 4 = 5


Last term an = 109


We that the nth term of an AP is

an = a + ( n - 1 ) * d


=> 109 = 4 + ( n - 1 ) * 5


=> 109 = 4 + 5n - 5


=> 109 = - 1 + 5n


=> 109 + 1 = 5n


=> 110 = 5n


=> 110 / 5 = n


=> 22 = n


=> n = 22


Hence the nth term of an AP is 22.


Hope it helps!

Answer 2

Hi Mate !!

Here is your answer :

Question : Which term of airthmatic progression 4 , 9 , 14 , 19 , ....... is 109.

Solution :

AP = 4 , 9 , 14 , 19 , ..............

Here,

First term ( a ) = 4

Common difference ( d ) = 9 - 4 = 5.

Tn = 109

a + ( n - 1 ) * d = 109

4 + ( n - 1 ) * 5 = 109

4 + 5n - 5 = 109

5n - 1 = 109

5n = 109 + 1

5n = 110

n = 110 / 5

n = 22

Hence,

therefore the 22th term of the given AP will be 109.

Hope it helps you ♥

By Rishi403.

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