which term of G.P √3,3,3√3,.....is729?
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First term of the G. P., r = √3
Common ratio, r = 3 / √3 = √3
An = ar ^( n-1 )
729 = √3 × √3 ^ ( n - 1 )
729 = √3 ^ n
√3^12 = √3^n
Bases are same, so their powers will become equal.
n = 12.
So, 12 th term of the G. P. is 729.
Common ratio, r = 3 / √3 = √3
An = ar ^( n-1 )
729 = √3 × √3 ^ ( n - 1 )
729 = √3 ^ n
√3^12 = √3^n
Bases are same, so their powers will become equal.
n = 12.
So, 12 th term of the G. P. is 729.
Anonymous:
3^6 = 729, so, √3 ^12. Just calculate it.
3^6 or √3 ^12 = 729
We cannot divide √3 as here is it's power ( n - 1 ). So, we have to make √3 in L. H. S. so that we can cancel it out. on both sides and get he value of n.
√3 should be there on both sides , then their powers will become equal.
Wlcm
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