Question

which term of GP 3,9, 27.......
is 729​

Answer 1

Step-by-step explanation:

3 , 9 , 27 ,........

Let the nth term of GP is 729

then , An = 729

ar^n-1 = 729

3(3)^n-1 = 729

3^n = 3^6

n = 6

So , the 6th term of this GP is 729 .

Answer 2

Answer:

3,9,27, 81 , 243,729

Step-by-step explanation:

let check is correct or not

• 3*3=9
• 9*3=27
• 27*3=81
• 81*3=243

• 243*3=729

each and everyone is multiplied by 3

hope its help you

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