Question

Which term of progression -1



,-3,-5???is -39;?

Answer 1

ARITHMETIC PROGRESSION:-

The given ap is as follows :

$\boxed{\boxed{(-1),(-3),(-5),...}}$

here,

a=(-3)

d= -3+1=(-2)

now,

Let the nth term of the AP be equal to (-39)

so,

a+(n-1)d=(-39)

(n-1)(-2) = (-39)+3 = (-36)

(n-1) = (-36)/(-2) = 18

n = 18+1 = 19

$\rule{200}{2}$

Hence,

The 19 th term of the given AP is equal to (-39)

Answer 2

Answer:

Here a=-1

D=-3- (-1)=-2

Nth term is -39

Tn=a +(n-1)d

=-39=-1+(n-1)-2

=-39+1=(n-1)2

=-38)-2=(n-1)

=19=(n-1)

=n=19+1

n=20

Step-by-step explanation: