Question

Which term of sequence 1,5,9,13...... is 77​

Answer 1

Answer:

given,

a=1, d=5-1=4, l=77

l=a+(n-1)d

77=1+(n-1) 4

77=1+4n-4

77=4n-3

4n=77+3

n=80/4

=20

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Answer 2

Answer:

$given \: sequence \: \\ 1 \: 5 \: 9 \: 13.......$

$a = 1 \\ d = 5 - 1 = 4$

$\huge\mathsf{t}$ $\small\mathsf{n}$ = $a(n-1)d$

$77 = 1 + (n - 1)4 \\ 77= 1 + 4n - 4 \\ 77 = 4n - 3 \\ 77 + 3 = 4n \\ 80 = 4n \\ n = \frac{80}{4} = 20$

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