Question

which term of series 16,14, 12
are o and -16​

Answer 1

Answer:

first term(a) = 16

common difference (d) = -2

nth term = a+ (n-1) d

0 = 16 + ( n-1) (-2)

0 = 16 + (-2n+2)

0= 18-2n

2n=18

n=9

-16= 16+(-2n+2)

-16= 18-2n

2n = 34

n=17

therefore 0 is 9th term and -16 is 17th term of the A.P.

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