Question

which term of the a.p 121,117,113...is its first negative term

Answer 1

a=121, d=-4, let an=0

an=a+(n-1)d

0=121+(n-1)(-4)

-121=-4n+4

-125=-4n

n=31.25

since n has to be a whole no., therefore, the ans is 32 ( the no. next to 31.25)

hence the 32nd term is the first negative term

hope this help you

Answer 2

a= 121 d= -4
let an be 0
an= a + (n-1)d
0= 121+(n-1)-4
-121 = (n-1)-4
121=4n - 4
125=4n
n=125/4
n=31.25
n=32 (approx)

a32= a+31d
a32 = 121 + 31 × -4
a32 = 121 - 124
a32= -3


Hence , 0 is not first negative number
and 32 term is the first negative term


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