Question

Which term of the A. P. : 2, 6, 10, 14, ... will be 88 more than its 43rd term ?​

Answer 1

Answer:

let the required term be nth term

here a = 2, d = 4

so according to statement

nth term = 88 + 43rd term

so, a + (n - 1)d = 88 + a + 42d

(n - 1)×4 = 88 + 42×4

4n - 4 = 88 + 168

4n - 4 = 256

4n = 260

n = 65

so required term is 65.

Answer 2

Answer:

a=2

d=6-2

= 4

a43=a+(n-1)d

a43=2+(43-1)4

a43=2+(42)4

a43=2+168

a43=170

an-a43=88

an-170=88

an=88+170

a+(n-1)d=258

2+(n-1)4=258

2+4n-4=258

4n-2=258

4n=258-2

4n=256

n=256/4

n=64

64th term