Question

which term of the A.P 3, 11 , 19, 27, ..... is 547?

Answer 1

» In AP we know that :-

$= > t _{n} = a + (n - 1)d$
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» Here

» AP = 3,11,19......547

» a = 3

» d = 2nd term - 1st term
d = 11 - 3 = 8

» tn = 547

» n = ??

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» Plug the all values in formula, we get :-

$= > t _{n} = a + (n - 1)d \\ \\ > 547 = 3 + (n - 1)8 \\ \\ = > 547 - 3 = 8n - 8 \\ \\ = > 8n = 544 + 8 \\ \\ = > 8n = 552 \\ \\ = > n = \frac{552}{8} = 69$
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» HENCE, Fir given AP 69th term is 547

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Answer 2

Answer:

Step-by-step explanation:

hope you understood