Which term of the A.P 3,12,,21,30,....will be 90 more than its 50th term.
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AP- 3, 12, 21, 30....
a=3
d= 12-3 = 9
a₅₀ = a + (50-1) 9 {∵ aₙ = a + (n-1) d}
a₅₀ = 3 + (49× 9)
a₅₀ = 3 + 441
a₅₀ = 444
Let the nth term be the term (a₅₀ + 90), i.e, 534.
534 = 3 + (n-1) 9
534 - 3 = (n-1) 9
(n-1) 9 = 531
(n-1) = 531/9
n = 59 + 1
n= 60.
Hence the 60th term is 90 more than a₅₀.
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