Question

Which term of the A.P : 3, 15, 27, 39, .... will be 120 more than its 53rd term?

Answer 1

Answer:

63rd term

Step-by-step explanation:

common difference=d=12

first term =3

53 term=a+(53-1)*d

            =3+52*12=3+624=627

627+120=a+(n-1)*d

747=3+(n-1)*12

(n-1)*12=744

n-1=62

n=63

Answer 2

The 63rd term will be 120 more than its 53rd term.

Given:

First term a=3

Common difference d=12

Now,

a53= a+52d

      =3+52*12

      =3+624

      =627 -------> 1

Given,

a53+120

i.e, 627+120=747

⇒an=747

an=a+(n-1)d

747= 3 +(n-1)*12

747=3+12n-12

747=-9+12n

747+9=12n

756=12n

n=63

Therefore, a63= 120 + a53

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