Question

which term of the A.P.3,15,27,39,... will be 132 more than its 60th term​

Answer 1

Answer:

Step-by-step explanation:

Given AP : 3,15,27,39,.......

a = 3

d = 15 - 3 = 12

Given that a term is 132 more than its 60th term

Here T60 = a+ 59d

= 3+59(12)

= 3+708

= 711

Given that the term is 132 more than its 60th

= 711 + 132

= 843

⇒ Tn = 843

⇒ a+(n-1)d = 843

⇒ 3+(n-1)12 = 843

⇒ (n-1)12 = 843 -3

⇒ (n-1)12 = 840

⇒ (n-1) = 840/12

⇒ (n-1) = 70

⇒ n = 70 +1

∴ n= 71

∴The 71st term is the term that 132 more than the 60th term 

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Answer 2

Answer:

first of all you will divide 132 by 12 from which you will get the number 11 now add 11 in 60 then you will get 71 so the answer is 71st term