which term of the A.P.3,8,13,18,...is 78?
Answers
Answered by
2
Solution :
A.P : 3,8,13,18,..
a = 3 , d = 8-3 = 5
An = 78
a+(n-1)d = 78
3+(n-1)5 = 78
(n-1)5 = 78-3
(n-1)5 = 75
(n-1) = 75/5
(n-1) = 15
n = 15+1
=> n = 16
Hence 78 is the 16 th term of Given AP.
A.P : 3,8,13,18,..
a = 3 , d = 8-3 = 5
An = 78
a+(n-1)d = 78
3+(n-1)5 = 78
(n-1)5 = 78-3
(n-1)5 = 75
(n-1) = 75/5
(n-1) = 15
n = 15+1
=> n = 16
Hence 78 is the 16 th term of Given AP.
RehanAhmadXLX:
:-)
Answered by
2
Heya friend,
Here is your answer,
Since the following sequence is in AP,
Therefore,
First term (a) = 3
Common difference (d) = 8 - 3 = 5
Tn = 78
Now, applying the formula for AP,
Tn = a + (n - 1)×d
=> 78 = 3 + (n - 1)×5
=> 75 = 5n - 5
=> 80 = 5n
=> n = 80/5
=> n = 16 (ans)
Therefore, 16th term of this AP will be 78.
Hope it helps you.
Thank you.
Here is your answer,
Since the following sequence is in AP,
Therefore,
First term (a) = 3
Common difference (d) = 8 - 3 = 5
Tn = 78
Now, applying the formula for AP,
Tn = a + (n - 1)×d
=> 78 = 3 + (n - 1)×5
=> 75 = 5n - 5
=> 80 = 5n
=> n = 80/5
=> n = 16 (ans)
Therefore, 16th term of this AP will be 78.
Hope it helps you.
Thank you.
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