Question

which term of the A.P 3,8,13...are 78.​

Answer 1

Step-by-step explanation:

$t2 - t1 = d \\\\ 8 - 3 = 5$

therefore the distance of AP. is 5

Answer 2

given arithmetic series is 3,8,13,...…78,...

common difference (d)= 8-3=5

first term a=3

we now nth term of A.P=a+(n -1)d

here nth term =78

78=3+(n - 1) 5

75=5n-5

5n=80

n=80/5=16

therefore 78 is the 16th term of given arithmetic series