Question

Which term of the A.P. 36, 33, 30, 27, ... is the first negative term?

Answer 1

Step-by-step explanation:

a=36, d = 33-36 = -3

By the general formula

: a+(n-1)d < 0

36+(n-1)-3< 0

36 - 3n + 3 < 0

39 - 3n < 0

- 3n < -39 ( cancel (-) both side )

3n < 39

n < 39/3

n < 13

therefore,

the first negative term will be 13

,,, hope this help you

Answer 2

Given:

Term of the A.P. 36, 33, 30, 27, ...

To find:

Which term of the A.P. 36, 33, 30, 27, ... is the first negative term?

Solution:

1) Let the nth term of the given A.P is negative so the aₙ term of the A.P is given by:

aₙ= a+(n-1)d < 0

• where a is first term = 36

• d is common difference which is 33-36 = -3

2) So the term we get is:

• 36+(n-1)(-3)< 0

• 36 - 3n + 3 < 0

• 39 - 3n < 0

• 39 < 3n

• 39/3 < n

• n > 13

which means n = 14

Hence, 14th term of the given AP will be the first negative term.