Question

Which term of the A.P 4, 9, 14, .... is 109?​

Answer 1

Step-by-step explanation:

AP =4,9,14..........109

HERE a =4

d=5

an=109

using an=a +(n-1)d

so , 109= 4+(n-1)5

109=4+5n-5

110=5n

n=22

therefore that is 22 term

Answer 2

Answer:

Given

a = 4

a2 = 9

a3=14

d = a2-a =9-4 =5

n=?

an =109

Solution

an = a+(n-1)d

109 = 4+(n-1)5

109-4 = 5n-5

105-5 = 5n

100/5 = n

20 = n

20th term is 109

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