Which term of the A.P. 52, 48, 44, 40 …..is zero?
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Answer:
Given,the A.P. is–
52,48,44,40....
here, a= 52
d= 48-52
= -4
an= 0
so, n= ?
now,
an= a+(n-1)d
= 0= 52+(n-1)(-4)
= -52= (n-1)(-4)
= (n-1)(-4)= -52
= n-1= (-52)/(-4)
= n-1= 13
n= 13+1
n= 14
so, the 14th term of the A.P. is zero.
Step-by-step explanation:
Formula–
an= a+(n-1)d
where,a= first term
d= common difference
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