Question

Which term of the A.P. 6, 10, 14, … is 102? Also find the sum.

Answer 1

Answer:

a=6

d(common difference)=4

Tn = a + (n - 1) d, where Tn = nth term and a = first term.

102= 6 + (n-1)4

96=(n-1)4

24=n-1

n=25

Answer 2

Answer:

,these pages are your answer with explanation