Question

Which term of the A.P. 88,84,80,...., is 0 ?

Answer 1

Answer:

92,88,84,80,...

a=92

d=88-92=84-88= -4

let nth term be 0

tn=a+(n-1)d

0 = 92 + (n-1)-4

0=92-4n+4

0=96-4n

4n=96

n=24

Answer 2

Answer:

The 23rd term of the A.P is 0.

Step-by-step explanation:

Given:

• A.P is 88, 84, 80.....

To Find:

• Which term of the A.P is 0

Solution:

First we have to find the coomon difference of the A.P

First term of the A.P = 88

Common difference = a₂ - a₁

Common difference (d) = 84 - 88 = -4

Now we have to find which term of the A.P is 0

The nth term of an A.P is given by,

aₙ = a₁ + (n - 1) × d

where aₙ = last term = 0

Substitute the data,

0 = 88 + (n - 1) × -4

88 - 4n + 4 = 0

92 - 4n = 0

4n = 92

n = 92/4

n = 23

Hence the 23rd term of the A.P is 0.

Verification:

aₙ = 88 + (23 - 1) × -4

aₙ = 88 + 22 × -4

aₙ = 88 - 88

aₙ = 0

Hence verified.