Which term of the A.P 9,12,15 is 132
Answers
Answered by
41
given series in AP
a = 9
d = 3
we know that
an = a+(n-1) d
132 = 9+(n-1) 3
41 = n-1
n = 42
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Answered by
11
Answer
a = 9
d = 3
an = a + (n - 1)d
132 = 9 + (n - 1)3
132 = 9 + 3n - 3
132 - 9 + 3 = 3n
126 = 3n
42 = n
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