Question

which term of the AP 1,3,5,....is 103​

Answer 1

Solution

$a_ 1 = a = 1$

$d = a_2 - a_1 \\ d = 3 - 1 \\ d = 2$

$a_n = 103$

$a_n = a + (n - 1)d$

$103 = 1 + (n - 1)2 \\ 103 = 1 + 2n - 2 \\ 103 = 2n - 1 \\ 103 + 1 = 2n \\ 2n = 104 \\ n = \frac{ 104}{2} \\ \\ n = 52$

So, the 52th term is 103