which term of the AP 1/3q, 1-6q/3q, 1-12q/3q
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Answer:
Step-by-step explanation:
a=1/3q
d=a2-a1
=(1-6q/3q)-(1/3q)
=-2
an=a+(n-1)d
=1/3q+(n-1)-2
=1/3q-2n+2
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