which term of the AP 1+4+7+10+........ .is 52
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Answered by
3
hey mate
a=1 d=4-1=3
a+(n-1)d=52
1+(n-1)3=52
1+3n-3=52
3n-2=52
3n=52+2
3n=54
n=54/3
n=18
a=1 d=4-1=3
a+(n-1)d=52
1+(n-1)3=52
1+3n-3=52
3n-2=52
3n=52+2
3n=54
n=54/3
n=18
cinderallav282:
the answer is suppose to be 18
Answered by
1
Here's the answer !!
We know that in an AP we can calculate the first term, common difference, number of terms and the Nth term by using the formula :
Aₓ = a + ( x - 1 ) d
Here x represents the number of terms.
So we know that,
Aₓ = 52, d = 3, a = 1
We need to find x = ?
So substituting in the formula we get,
52 = 1 + ( x - 1 ) 3
=> 52 - 1 = 3 ( x - 1 )
=> 51 = 3 ( x - 1 )
=> ( x - 1 ) = 51 / 3
=> x - 1 = 17
=> x = 17 + 1 = 18 th term.
Hence 52 is the 18th term of the given AP.
Hope my answer helps !!
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