Question

Which term of the AP 1.5, 4.5, 7.5, ... is 25.5?


answer it fast...please​

Answer 1

Answer:

9th term

Step-by-step explanation:

first term(a) = 1.5

common difference (d)=4.5-1.5=3.0

Tn=25.5

n=?

Tn= a+(n-1)d

25.5=1.5+(n-1)3

25.5-1.5=3n-3

24+3=3n

27=3n

n=9

Hope it helps u

Answer 2

Here,

Here, t1,a= 1.5

Here, t1,a= 1.5 Common difference,d= t2-t1 =4.5-1.5 =3

Here, t1,a= 1.5 Common difference,d= t2-t1 =4.5-1.5 =3 Let tn =25.5

Here, t1,a= 1.5 Common difference,d= t2-t1 =4.5-1.5 =3 Let tn =25.5So,

Here, t1,a= 1.5 Common difference,d= t2-t1 =4.5-1.5 =3 Let tn =25.5So, a+(n-1)×d=tn

Here, t1,a= 1.5 Common difference,d= t2-t1 =4.5-1.5 =3 Let tn =25.5So, a+(n-1)×d=tn => 1.5+(n-1)×3=25.5

Here, t1,a= 1.5 Common difference,d= t2-t1 =4.5-1.5 =3 Let tn =25.5So, a+(n-1)×d=tn => 1.5+(n-1)×3=25.5 => 1.5+3n-3=25.5

Here, t1,a= 1.5 Common difference,d= t2-t1 =4.5-1.5 =3 Let tn =25.5So, a+(n-1)×d=tn => 1.5+(n-1)×3=25.5 => 1.5+3n-3=25.5 =>3n-1.5=25.5

Here, t1,a= 1.5 Common difference,d= t2-t1 =4.5-1.5 =3 Let tn =25.5So, a+(n-1)×d=tn => 1.5+(n-1)×3=25.5 => 1.5+3n-3=25.5 =>3n-1.5=25.5 =>3n=27

Here, t1,a= 1.5 Common difference,d= t2-t1 =4.5-1.5 =3 Let tn =25.5So, a+(n-1)×d=tn => 1.5+(n-1)×3=25.5 => 1.5+3n-3=25.5 =>3n-1.5=25.5 =>3n=27 =>n=9

Here, t1,a= 1.5 Common difference,d= t2-t1 =4.5-1.5 =3 Let tn =25.5So, a+(n-1)×d=tn => 1.5+(n-1)×3=25.5 => 1.5+3n-3=25.5 =>3n-1.5=25.5 =>3n=27 =>n=9So,

t9=25.5....9th term is 25.5