Question

which term of the AP 12,7,2,3 ...... is -98​

Answer 1

Answer:

$a = 12 \\ d = - 5 \\ tn = - 98 \\ a + (n - 1)d = - 98 \\ 12 + (n - 1) (- 5 )= - 98 \\ (n - 1) - 5 = - 110 \\ n - 1 = ( - 110 )\div (- 5) \\ n - 1 = 22 \\ n = 22 + 1 \\ n = 23$

Answer 2

$\huge\boxed{Answer:}$

Let nth term be -98

Given,,,12,7,2,-3.....Are in AP

And a=12 , d = -5

Since,,.  an = -98

         a+(n-1)d = -98

          12+(n-1)(-5) = -98

              (n-1)(-5) = -98-12

              (n-1)(-5) = -110

               (n-1) =  (-110) / (-5)

              (n-1) = 22

              n = 22 + 1

             n = 23

Hence,,,,,23rd term be - 98.

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