Question

which term of the AP 13,20,27,... is 384?​

Answer 1

Step-by-step explanation:

The required A.P is 13,20,27,..., 384.

Here a=13 , d= t2-t1 = 20-13 = 7 , tn = 384

n=?

Therefore, tn = a + (n-1 ) d

t384= 13 + ( n-1 ) 7

384 = 13 + ( n-1 ) 7

384 -13 = ( n-1 ) 7

371 = 7n - 7

7n = 371 + 7

7n = 378

n= 378

7

n= 54

The nth terms of A.P is 54.

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Answer 2

Answer:

a=13 d=a2-a1 an=384

=20-13

=7

an=a+(n-1)d

384=13+(n-1)7

384-13=7n-7

371+7=7n

378=7n

n=378/7

n=54

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