Question

which term of the Ap:2,4,6,8........126?​

Answer 1

Answer:

126 will be the 61 th term

Step-by-step explanation:

$an = 126 \\ a = 2 \\ d = a2 - a1 \\ = 4 - 2 = 2 \\ now \: putting \: tham \: in \: equation \\ an = a + (n - 1)d\\ 126 = 2 + (n - 1)2 \\ 126 = 2 + 2n + 2 \\ 126 = 2n + 4 \\ 126 - 4 = 2n \\ 122 = 2n \\ n = \frac{122}{2} \\ n = 61$

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