which term of the AP 20 , 19 1/4 , 18 1/2
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The given A.P is 20, 19 1/4, 18, 1/2...
Hence, a= 20
d= 19 1/4 -20 = -3/4
Let the nth term of the A.P be the first negative term. Then,
an< 0
=) a+ (n-1)d
=)20 +n(-1) (-3/4)<0
=) 20< (n-1) (3/4)
=)(n-1) (3/4)>20
=)(n-1)> 20/3/4
=)(n-1)>20 ×4/3
=)(n-1)>80/3
=) n> 80/3 +1
=) n> 80+3/3
=) n> 83/3
=)n> 27 2/3
Least integral value of n= 28.
Hence, 28nd term of the given A.P is the first negative term.
hope it helps ✔️
abhinav200410:
OK thanks
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