Which term of the AP 21,42,63,84,...... is 120?
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Step-by-step explanation:
given that ,
first term = 21
common difference = 42 - 21 = 21
last term = 120
then ,
an = a + ( n - 1 ) d
120 = 21 + ( n - 1 ) 21
120 - 21 = 21n - 21
99 = 21n - 21
99 + 21 = 21n
120 = 21n
n = 120 / 21
n = 40 / 7
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