Math, asked by Sivakumarhct, 1 year ago

Which term of the AP 23,46,69,92,.....is 437?

Answers

Answered by Manikumarsingh
11
437= 23+(n-1)23
437-23=(n-1)23
414=(n-1)23
n-1=414/23
n-1=18
n=18+1=19
Answered by Ankit1408
10
hello friends.....
solution,
here
a= 23
d= 46 - 23= 69-46 = 23

here given that
An= 437

now using formula
An= a+(n-1) d
437 = 23 +(n-1) 23
437 = 23n
=> n = 19 answer

♦ hope it helps ♦
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