Which term of the AP 3,12,21,30,.will be 90 more than its 50" term.
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3
Answer:
d = 12- 3
= 9
a + (n-1) d = 90 + (a +49d)
3+ (n-1) 9 = 90 + 3 + 441
(n-1) 9 = 534 - 3
(n-1) = 531/9
n-1 = 59
n = 60th term
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an_ a+(n-1)d a50_ 3+49*9_444
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