Question

which term of the AP 3,14,25,36 will be less than 121 then it's 37th term?​

Answer 1

Here,a= 3,d = 11,

Now,first find 37th term

a37 = a+36 d

a37 = 3+36×11

a37 = 3+396 = 399

So,an(term to find) will be =

an = a37-121

an = 399-121 = 278

So,now

an = a+(n-1)d

278 = 3+(n-1)(11)

275 = (n-1)(11)

25 = n-1

So,n = 25

Hence,25th term of the AP is 121 smaller than it's 37th term

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