Question

Which term of the ap 3,15,25,39 will be 132 more than 54th term

Answer 1

hey
the following a.p.is 3,15,25,39
here a =3
d(common difference)=a2-a1
=15-3
=12
a54 will be 3+53*12
because an =a +(n-1) d
= 639


but we need 132 more than it which will be 771 now we will find no. of term it is by the same formula above .
771 =3+(n-1)12
768=(n-1)12
768/12 = n-1
64+1 = n

thus it will be 65th term .


hope this might help you

Answer 2

☺ Hello mate__ ❤

◾◾here is your answer...

Lets first calculate 54th of the given AP.

First term = a = 3

Common difference = d =15 - 3 = 12

Using formula an=a+(n−1)d,  to find nth term of arithmetic progression, we get

a54=a+(54−1)d

a54=3+53(12)=3+636=639

We want to find which term is 132 more than its 54th term. Lets suppose it is nth term which is 132 more than 54th term.

Therefore, we can say that

an=a54+132 

......{an=a+(n−1)d=3+(n−1)(12)}{a54=639}

⇒3+(n−1)12=639+132

⇒3+12n−12=771

⇒12n−9=771

⇒12n=780

⇒n=780/12=65

Therefore, 65th term is 132 more than its 54th term.

I hope, this will help you.

Thank you______❤

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